Re: [KrisFlyZ] new BASE wing suit method?
KrisFlyZ wrote:
What do you think caused that force(Lift)?
The force(Lift + Drag) is a result of the airspeed that didn't exist when the jumper was in the plane. Let's not split hairs here.
A better way to understand it: The force is a function of the jumper's horizontal kinetic energy, which certainly
did exist while the jumper was in the plane. By exiting the aircraft, the wingsuit flyer has a chance to convert that kinetic energy into potential energy. Your sum vector is a function of "airspeed," not "rate of change of airspeed."
I agree that, assuming weight stays unchanged, and thrust remains zero, the sum force equals lift + drag. the lift component of that equation is based on the lift equation which i mentioned previously. drag is the sum of induced drag and parasite drag. None of the above anything to do with the rate of change of airspeed in this case.
not splitting hairs here... it's just physics!
What is the airspeed of the jumper at the peak of their climb, after stepping off the tailgate? It's not 160 knots any more...
In reply to:
Not the same climb. If that were possible, the jumper will be subject to the same force.
i feel like you are intending to talk about a force, but are actually referring to the rate of change of a force.
In reply to:
If the jumper arrives at 160 knots horizontal speed with 30 degrees AoA, the force vector is now pointing in a different direction as the AOA is Glide Angle(arctan(D/L)) + Pitch(negative if below horizon). This force has a smaller component pointing vertically up and there is an additional vertical momentum that must be overcome.
I would define AOA for a wingsuiter as the angular difference between the angle of the velocity vector of the jumper, and the angle of the mean aerodynamic chord of the jumper. Therefore, AOA is not directly a function of glide angle. In a straight, unaccelerated glide, it is permissible to use pitch and glide angle to get a very good estimate of AOA. But they are not the true determinants of it.
in the case of "this additional vertical momentum" (which I assume you mean in the downward direction), then we are not talking about an object in level, horizontal flight. instead, you are talking about an object that is descending. You are merely describing that the jumper who immediately exited the C-130 has a velocity vector with components of 160 knots horizontally and zero knots vertically. and for the hypothetical jumper in mid-flight, I take it that you are proposing them to have a constant 160 knots horizontal component as well as some downward component as well. This is where we are not on the same page, it seems.
You are talking about a jumper in mid flight, gliding 160 knots in unaccelerated, descending flight. I am talking about a jumper in mid flight, gliding at 160 knots in decelerating, level flight. Trading his airspeed to maintain altitude.
(level in this sense means not climbing or descending, as opposed to "not in a turn")
Theoretically, if the jumper has enough kinetic energy, he can trade it for potential energy.
theoretically. All i'm saying is that there is nothing in the laws of physics that could prevent a properly designed wingsuit, flown by a skilled-enough flyer, from physically (and momentarily) gaining altitude after a dive.
"jus' sayin"