Re: [TomAiello] Can YOU see something wrong here??
In reply to:
I'd like to see it. Either here, or via email or PM.
it may be a bit off topic, but at the moderator's request...
I pulled out my first textbook regarding aerodynamics.
(Introduction to Flight by John D. Anderson, Jr. 1978, McGraw-Hill)
section 4.3 on pages 69-73 discuss momentum along a streamline. (a stream line is the path along which an infinitesimally volume of air flows.)
mass:
the volume of the piece of air is dx dy dz.
therefore it's mass = ro(dx dy dz) (ro is the density of air)
acceleration:
a = dV/dt = DV/dx dx/dt = DV/dx V (V is velocity, t is time)
Newton:
F=ma
-dp/dx (dx dy dz) = ro(dx dy dz)V dV/dx (p is pressure)
(pressure x area = F = ma)
dp = -ro V dv (Euler's equation)
or
dp + ro V dV = 0
integrating it along a streamline yields
p + 1/2 ro V^2 = constant (Bernoulli's equation)
(static pressure + dynamic pressure = total pressure = constant)
static pressure is the pressure as measured perpendicular to the airstream.
dynamic pressure is the pressure resulting from the motion of the air.
assumptions:
-gravity is insignificant
-frictionless air
-the formula is for any point on the same streamline
-incompressible flow (i.e. ro is a constant)
"if all the streamlines have the same value of p and V far upstream, then the constant in Bernoulli's equation is the same for all streamlines."
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air cannot flow into a solid object.
at best it will flow parallel to the surface.
thus the pressures affecting a wing, and creating lift, are STATIC pressures.
freefalling bodies will feel TOTAL pressures.
otherwise the following statements conflict:
“the faster air over the top of the wing results in a lower pressure.”
“the faster you fall the ‘harder’ the air becomes.”
we would be better served if we prefaced “pressure” properly…
(side note: aircraft use pitot tubes to determine airspeed. these devices compare the pressure parallel to the airstream with that perpendicular to the airstream.)
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as far as pilot chutes go...
it is a very complicated situation.
at the risk of committing over-simplification,
obviously, the airflow within the pilot chute is less than the flow outside.
Bernoulli thus states that the static pressure within the pilot chute is greater than that without.
but, an uninflated pilot chute can not support a load. any hint of pressure differences will cause the fabric to move.
therefore, the phrases “the air inside an inflating pilot chute pushes the fabric out” or “the air flowing by the inflating pilot chute pulls the pilot chute out” are equally valid.