Re: [NickDG] Tanning Salon and BASE Jumps: This is for real.
> ...consider that the application of force on the breakcord is not a static load... ...your all up weight is accelerating away from S/L at the moment that weight is applied to the breakcord...
> ...but this increases the forces applied considerably
Well, let's see.
Our body in freefall
WOULD exert a high force.
Why "WOULD"? Simply because before break there no force applied anywhere (= not to a fixed point), gravity force is pulling you down and you accelerate, after break again gravity continues to pull you down.
Your body does exert a force
ON A STATIC/FIXED POINT only in the few split milliseconds you load the break cord and it breaks. Before putting tension on break cord and after break, there only gravity with no other force that opposes to it, simply it accelerates you.
The bottom line is the above: even if your accelerating body would be capable of exerting a high force onto a fixed ppoint, the break cord cannot hold yourself more than its proper break load.
Rather, I think an interesting argument is the following.
Granted that 100 lb - 45 lb applied statically to break cord loop breaks it, what would happen to our break cord loop if a device capable of applying a variable force (=your body in freefall) actually start exerting an increasing force onto the break cord loop?
When would the break cord loop break if such a variable force is applied dynamically/instantaneously to it?
Would the break cord loop dynamically break BELOW 100 lb - 45 lb?
Would the break cord loop dynamically break ABOVE 100 lb - 45 lb?
I think the dynamic test can only be performed in a laboratory, putting break cord strings between the clamps of a dynamometer and setting it to pull at a fixed speed (perhaps few test at different speeds) and having it to record the load applied between the clamps, up to break of loop. And having a look at the results, especially reading the load AT break.
If you take a 100 lb - 45 lb and apply it gradually to a break cord loop, at the very end of releasing it breaks the break cord loop.
Given for granted that if you step "very fast" over a brick on the pavement, you exert onto brick twice your weight (=dynamic load) just for a split millisecond and then you exert just your weight, if you step "very slowly" over a brick, at the end of slowly process of releasing/loading weight you end up with your weight onto brick.
So, if you take a 100 lb - 45 lb load and release it istantaneously onto a break cord loop, it
WOULD exert for a split millisecond twice its weight, but simply our break cord loop cannot hold such a weight and it breaks exactly AT its (dynamic) break load.
It would be really interesting to know if and how much the dynamic break load differs from the static break load of our 80 lb - 36 kg break cord.
If you don't believe to the fact that instantaneously applying a weight onto a surface, the surface itself bear for a split millisecond bear a load twice the weight of the object, try the following.
Take the scale you got at home.
First test: put only one foot onto the scale and very slowly transfer your weight from the foot on pavement to the foot onto the scale: you will notice that the indicator on the scale increases up to your weight, without never exceeding your own weight.
Second test: put only one foot onto the scale and transfer IMMEDIATELY, as fast as you can, your weight from the foot on pavement to the foot onto the scale: you will notice that the scale indicator will exceed your weight (you should read for a while twice your weight, but system itself could be not so fast in "chasing" the actual (maximum) weight value) and then, oscillating it will stabilize onto your weight.